12000: 【原2000】Sum of Sequence

题目

题目描述

author: xjia 原OJ链接：https://acm.sjtu.edu.cn/OnlineJudge-old/problem/2000

Description

Given a sequence of integers \( a_1, a_2, \dots, a_n \), calculate the sum of the sequence \( a_1 + a_2 + \dots + a_n \).

Input Format

Line 1: A positive integer \( n, 1 \leq n \leq 10000 \)

Line 2: A sequence of \(n\) integers \( a_1, a_2, \dots, a_n, \forall 1 \leq i \leq n, -10000 \leq a_i \leq 10000\)

Output Format

Line 1: An integer representing the sum of the sequence

Sample Input

3
4 5 6

Sample Output

15

Limits

Time limit: 500ms, memory limit: 50000kb.

ligongzzz's solution

#include "cstdio"
using namespace std;

int main() {
    int num,n;
    long long ans=0;
    scanf("%d", &num);
    for (int i = 0; i < num; i++) {
        scanf("%d", &n);
        ans += n;
    }

    printf("%lld", ans);
    return 0;
}

yyong119's solution

#include <cstdio>

int main() {

    long long sum = 0;
    int n; scanf("%d", &n);
    for (int i = 0; i < n; ++i) {
        int tmp; scanf("%d", &tmp);
        sum += tmp;
    }

    printf("%lld", sum);
    return 0;
}